Optics reflection/refraction problem

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SUMMARY

The discussion centers on a physics problem involving optics, specifically reflection and refraction in a water-filled tank with a refractive index of 1.33. Participants are tasked with determining visibility of marks on the tank's wall from an observer's eye level at the top of the water. The relevant equation for this problem is Snell's Law, expressed as n1sin(θ1) = n2sin(θ2). The conclusion indicates that the observer can see the marks from the top of the tank downwards, with the lowest visible mark being the 0 cm mark.

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  • Understanding of Snell's Law in optics
  • Basic knowledge of refraction and reflection principles
  • Familiarity with the concept of refractive index
  • Ability to sketch ray diagrams for light paths
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  • Explore the concept of critical angle and total internal reflection
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Students studying physics, particularly those focusing on optics, as well as educators seeking to enhance their understanding of refraction and reflection principles in practical scenarios.

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Homework Statement



The 80 cm tall, 65 cm wide tank shown in the figure is completely filled with water (n=1.33). The tank has marks every 10 cm along one wall, and the 0 cm mark is barely submerged. As you stand beside the opposite wall, your eye is level with the top of the water.

a.) Can you see the marks from the top of the tank (the 0cm mark) going down, or from the bottom of the tank (the 80cm mark) coming up? Explain

b.) Which is the lowest or highest mark, depending on the your answer to part a, that you can see?

Homework Equations



I'm not sure what equations are relevant. maybe snell's law? n1sin\vartheta2=n2sin\vartheta2

The Attempt at a Solution



I'm really not sure where to even start.
** drawing is attached.
 

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Sketch the rays coming form the marks to your eye.
 


He's looking for a mathematical answer, not just a drawing. Any ideas on how to do that?
 

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