Related Rates: Calculating the Pressure Change in a Gas Container

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Homework Help Overview

The discussion revolves around a related rates problem involving the pressure change in a gas container. The original poster presents a scenario where the pressure and the rate of change of temperature are given, but there is uncertainty regarding the temperature value at the initial time.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the derivative of the pressure with respect to temperature and express confusion about determining the temperature value at t=0. There is also a focus on the interpretation of the temperature rate given in the problem statement.

Discussion Status

Some participants have pointed out the ambiguity in the problem's wording and suggest seeking clarification from the instructor. There is acknowledgment of the original poster's approach to the problem, but no consensus on how to proceed has been reached.

Contextual Notes

Participants note that the temperature rate provided may not be a standard temperature value, leading to questions about the assumptions that can be made regarding the initial conditions of the problem.

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Homework Statement



A container of constant volume contains a quantity of gas under pressure. At t=0, the pressure is 4 psi and the temperature is 15°C per minute. What is the rate of change of the pressure inside the container at time t=0?

Homework Equations



[itex]\frac{P}{T}[/itex] = constant

The Attempt at a Solution



Taking the derivative of both sides and then simplifying, I ended up with:

T[itex]\frac{dP}{dT}[/itex] - P[itex]\frac{dT}{dT}[/itex] = 0

So solving for dP/dt:

[itex]\frac{dP}{dt}[/itex] = [itex]\frac{P}{T}[/itex][itex]\frac{dT}{dt}[/itex]

This is where I get stuck. I know P = 4 psi and dT/dt = 15°C per minute, but I can't figure out how to determine T. Without knowing the actual value of the constant in the original formula, I don't see how it is possible. The wording of the temperature value in the problem sounds odd to me. The only thing I can think of is that the temperature should be assumed to be 0°C at t=0 and so dP/dt does not exist. Is this it, or am I missing some way to find T?
 
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pry_or said:

Homework Statement



A container of constant volume contains a quantity of gas under pressure. At t=0, the pressure is 4 psi and the temperature is 15°C per minute.
15°C per minute is not a temperature. It's the time rate of change of temperature. What is the exact wording of this problem?
pry_or said:
What is the rate of change of the pressure inside the container at time t=0?

Homework Equations



[itex]\frac{P}{T}[/itex] = constant

The Attempt at a Solution



Taking the derivative of both sides and then simplifying, I ended up with:

T[itex]\frac{dP}{dT}[/itex] - P[itex]\frac{dT}{dT}[/itex] = 0

So solving for dP/dt:

[itex]\frac{dP}{dt}[/itex] = [itex]\frac{P}{T}[/itex][itex]\frac{dT}{dt}[/itex]

This is where I get stuck. I know P = 4 psi and dT/dt = 15°C per minute, but I can't figure out how to determine T. Without knowing the actual value of the constant in the original formula, I don't see how it is possible. The wording of the temperature value in the problem sounds odd to me. The only thing I can think of is that the temperature should be assumed to be 0°C at t=0 and so dP/dt does not exist. Is this it, or am I missing some way to find T?
 
That is the exact wording of the problem. That's why I said the wording was odd.
 
Whoever wrote the problem made a mistake. I would get some clarification from the instructor as to what the real problem is.
 
That's what I expected, thank you!
 

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