Related Rates Problem: 13m Ladder Leaning Against Wall

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The problem involves a 13m ladder leaning against a wall, with the top of the ladder slipping down at a rate of 2m/s. The user applied the Pythagorean theorem to establish the relationship x² + y² = 13², where x is the distance from the wall and y is the height of the ladder on the wall. By differentiating implicitly, the user derived the equation 2x(dx/dt) + 2y(dy/dt) = 0 and calculated the foot of the ladder moving away from the wall at a rate of 5/6 m/s when the top is 5m from the ground. This solution is confirmed as correct.

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raoulduke1
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Could someone verify my answer for this question?

13m ladder is leaning against a wall.
If the top of the ladder slips down the wall at a rate of 2m/s.
How fast will the foot be moving away from the wall when the top is 5m from the ground?

My answer:

use pythagoras to set up equation x^2 + y^2 = 13^2

Then I differentiate this implicitly and get the equation 2x dx/dt + 2y dy/t = 0

Then I fill in the values and get 5/6 m/s.

Is this correct?
 
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That is correct. I did it another way though, using a formula for dh/db.
 

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