Related Rates: Calculating Height and Radius of a Conical Pile

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SUMMARY

The discussion focuses on calculating the rate of change of height and radius of a conical pile of sand, where sand is deposited at a rate of 10 m³/min. The relationship between height (h) and radius (r) is defined by the equation h = 3/8 * 2r. To solve the problem, participants are encouraged to derive the volume of the cone using the formula V = (1/3)πr²h, which will facilitate finding the rates of change of height and radius with respect to time when the pile reaches a height of 4 meters.

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  • Understanding of related rates in calculus
  • Familiarity with the volume formula for a cone: V = (1/3)πr²h
  • Knowledge of implicit differentiation
  • Basic algebra for manipulating equations
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  • Study the derivation of the volume formula for a cone
  • Practice implicit differentiation with real-world applications
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Homework Statement


Sand falls from a conveyor belt at the rate of 10 m^3/min onto the top of a conical pile. The height of the pile is always three-eighths of the base diameter. How fast are the a) height and b) radius changing when the pile is 4m high?


Homework Equations


h = 3/8 * 2r


The Attempt at a Solution


I'm not sure where to start. I just need a small hint.
 
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The question is giving you dV/dt. What's the equation for the volume of a cone in terms of r and h? That's a small hint.
 
More than enough. Thanks
 
The rate of change of the volume of the cone is 10 m3 per minute. What is the expression for the volume of a cone in terms of its height and base radius? This will allow you determine dr/t or dh/t in terms of dV/dt.

EDIT: two minutes too late...
 

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