Related Rates Sand Pile Problem

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Homework Help Overview

The problem involves a machine dumping sand at a constant rate, forming a conical pile where the height is always twice the base diameter. Participants are tasked with determining how fast the height and the area of the base are increasing after a specified time.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate the volume of the cone to the rate of change of height and base area, using the given relationship between height and radius. Some participants question the application of this relationship to the second part of the problem regarding the area of the base.

Discussion Status

Participants are actively discussing the relationships between the variables involved. Some guidance has been offered regarding the height and diameter relationship, and hints have been provided for rewriting the area equation. There is acknowledgment of the correctness of the first part of the problem, but uncertainty remains about the second part.

Contextual Notes

Participants note the need to check units in their calculations and express uncertainty about how to approach the second question regarding the area of the base.

Mr Davis 97
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Homework Statement


A machine starts dumping sand at the rate of 20 m3/min, forming a pile in the shape of a cone. The height of the pile is always twice the length of the base diameter. After 5 minutes, how fast is the height increasing? After 5 minutes, how fast is the area of the base increasing?

Homework Equations



V = (1/3)(pi)r^2(h)

The Attempt at a Solution


[/B]
For the first question,
##h = 4r##
##\displaystyle V(t) = 20t = \frac{1}{3}\pi r^2 h = \frac{\pi}{48}h^3##
From this equation I get
##\displaystyle h = (\frac{960}{\pi}t)^{\frac{1}{3}}##
then
##\frac{dh}{dt} = \frac{320}{\pi ((\frac{960}{\pi})t)^{\frac{2}{3}}}##
When 5 is substituted for t, I get 0.77 m^3/min. Is this correct?

Also, I am not sure how to approach the second problem. I know that the area of the base is ##\pi r^2##, but I am not sure how to proceed...
 
Last edited:
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Use the fact that height is equal to twice the diameter of the base at all times.
 
Last edited:
Thewindyfan said:
Use the fact that height is equal to twice the diameter of the base at all times.
I did that for the first problem. I don't see how it will work for the second problem though.
 
Mr Davis 97 said:
I did that for the first problem. I don't see how it will work for the second problem though.
EDIT: ah never mind, fairly straightforward problem. Haven't seen one like this in awhile though.

Method 1: If you're know what dH/dt is, try applying that to see what the radius would be.

EDIT: you did the first part right.
Suggested Hint: Try rewriting the area equation.

...and check your units to part 1.
 
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