Related Rates + HOw to find a variable

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Homework Help Overview

The discussion revolves around a related rates problem involving the rate at which gravel is being dumped to form a conical pile. The original poster is trying to determine how fast the height of the pile is increasing when the height is 10 ft, given the volume of the cone and the relationship between the height and radius.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to relate the height and radius of the cone, noting that they are equal. Some participants suggest using this relationship to simplify the volume equation to find the desired rate of change.

Discussion Status

Participants are exploring the relationship between the height and radius of the cone and how it affects the volume. Some guidance has been offered regarding eliminating the radius from the volume equation, but there is no explicit consensus on the approach yet.

Contextual Notes

The original poster expresses confusion about the relationship between height and radius, indicating a need for clarification on how to apply the given conditions to the problem.

madeeeeee
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Gravel is being dumped from a conveyor belt at a rate of 30 ft3/min and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 10 ft high?

Known:
dV/dt=30 ft^3/min
Cone Volume= 1/3(pi)(r^2)(h)

Unkown:
dh/dt= ? when h= 10ft

I am confused about how to find the height and radius of the pile if they are equal.
height=radius

Please help me with this thank you and i am sure that i will be able to solve this problem.
Thank you
 
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Use the relationship between height and radius to eliminate the radius from the volume relationship. Now you can find dV/dt and the required answer.
 
ok thank you

Also, if i have the function y=x^3-3x^2
is my horizontal asymptote 1?
 
madeeeeee said:
ok thank you

Also, if i have the function y=x^3-3x^2
is my horizontal asymptote 1?
?
This function does not have a horizontal asymptote. Did you mean x-intercepts? If so, there are two: x = 0 and x = 3.
 
ok, so does that mean that there is also no, vertical or slant asymptote?
 
y = x^3 - 3x^2 doesn't have any asymptotes at all.
 
ok thank you
 

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