Relating orthogonal accelerations in special relativity

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SUMMARY

This discussion centers on relating orthogonal accelerations in special relativity between two frames: an inertial frame S and the instantaneous inertial reference frame S' of an accelerating particle. The acceleration components are denoted as (a_x, a_y) in frame S and (a_x', a_y') in frame S'. The key conclusion is that the relationship between the y-components of acceleration is given by the equation a_y' = γ²a_y, where γ is the Lorentz factor. The reasoning presented critiques Morin's application of the chain rule and emphasizes the implications of Lorentz transformations on the velocity of the particle.

PREREQUISITES
  • Understanding of special relativity concepts, particularly Lorentz transformations.
  • Familiarity with acceleration and its components in different reference frames.
  • Knowledge of the chain rule in calculus as it applies to physics.
  • Basic grasp of the Lorentz factor (γ) and its significance in relativistic physics.
NEXT STEPS
  • Study the derivation and implications of Lorentz transformations in special relativity.
  • Explore the relationship between acceleration and velocity in different inertial frames.
  • Investigate the application of the chain rule in relativistic contexts.
  • Examine Morin's approach to special relativity and compare it with other texts for a broader understanding.
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This discussion is beneficial for physics students, educators, and researchers focusing on special relativity, particularly those interested in the nuances of acceleration in different inertial frames.

LightPhoton
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TL;DR
Reasoning for the validity of relation between orthogonal accelerations in special relativity
We want to relate acceleration in two frames, an inertial frame S, and the instantaneous inertial reference frame of the particle on which it is being accelerated, S', which is moving in the ##x## direction at the moment. Let the acceleration in S be ##(a_x,a_y)## and in S' be ##(a_x',a_y')##. We want a relationship between them.

Now, here Morin argues that when consider the ##y## component we can write ##dy=dy'## and that ##dt'=dt/\gamma##, thus

$$a_y'=d^2y'/dt'^2=d^2y/(dt/\gamma)^2=\gamma^2a_y\tag1$$

But this seems wrong since we are taking the derivative of a factor of ##\gamma## here. If we go into a bit more detail then,


$$a_y=\frac{d^2y}{dt^2}=\frac d{dt}\bigg(\frac{dy'}{\gamma dt'}\bigg)=\frac1{\gamma^2}a_y'+\underbrace{\frac{dy'}{dt'}}_{v'}\frac d{dt}\bigg(\frac1{\gamma}\bigg)$$

but since the particle is at rest with respect to itself ##(v'=0)##, the second term goes to zero and we get ##(1)##. Is this reasoning correct?
 
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I think you are applying the chain rule here, and I agree that's the formally correct approach. However note that the structure of the Lorentz transforms, which are aligned parallel to the x axis, tells you that the velocity of the particle is parallel to x (otherwise you couldn't use these transforms to reach its rest frame). Hence ##dy/dt=0## in any frame, not just the rest frame.

I think that's why Morin is taking a shortcut here.
 
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