Relating the Reynolds number to the Drag Coeffient

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SUMMARY

The discussion centers on the relationship between the Reynolds number (Re) and the drag coefficient (Cd) in fluid dynamics. It is established that the drag coefficient must be determined experimentally for varying velocities, as it is influenced by factors such as velocity, density, characteristic length, and viscosity. The Reynolds number is defined as Re = (ρvl)/μ, while the drag force is typically proportional to the square of the velocity (v²). The conversation highlights the complexity of deriving Cd in terms of Re, particularly in high-viscosity mediums like seawater.

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Noone1982
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How does one relate the Reynolds number to the Drag Coeffient?

It seems the drag coefficient for different velocities must be determined experimentally per set. I know the Reynolds number is a method to determine laminar or turbulent flow, but can it be used to determine the drag coefficient?
 
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See discussion on drag coeffient and the relationship between drag force and velocity here.
http://www.grc.nasa.gov/WWW/K-12/airplane/dragco.html

In addition, Reynolds number is a function of velocity, and density, characteristic dimension (length), and viscosity.

One can relate Re and Cd through velocity.
 
Thank you for your response.

The Drag coefficient is given by,

\mbox{C}d\; =\; \frac{1}{2}\mbox{C}d\left( v \right)Apv^{2}

And the Reynolds number is given by,

\mbox{Re}\; =\; \frac{vpl}{\mu }

I'm failing to see how to solve Cd in terms of the Reynolds number since the Reynolds number doesn't contain a drag force.
 
Anyone? The clock is ticking :(
 
Taking Re\, =\, \frac{\rho vl}{\mu }, then

Re^2\, =\, \frac{(\rho vl)^2}{\mu^2 }, or

Re^2(\frac{\mu}{l})^2\, =\,(\rho v)^2}

The one looks at Cd

C_d\; =\; \frac{1}{2}C_d\left( v \right)A\frac{(\rho v)^{2}}{\rho}

then do appropriate substitution.
 
Does it matter if the medium has a very high viscosity? We were looking at a calculation in sea water with a Poise of 1.025. Some gents said that the calculation that we used should use v2 instead of v. What do the gurus think?
 
Unless you have some special kind of Cd, the drag force is usually proportional to v^2 rather than v. Without knowing what specific calculation you are talking about, deponent further sayeth not.
 

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