- #1

Ketan Vadher

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How will be the graph of varying acceleration and time if acceleration decreases?

Will it be a straight line with negative slope or any other shape?

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- Thread starter Ketan Vadher
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In summary: I do not know if this value of C is correct because I don't know if my initial assumption is correct, and I don't know the torque as a function of time.In summary, the conversation is about finding the relation between acceleration and time, and how it can be represented on a graph. The shape of the graph can vary depending on the changing acceleration, with a horizontal line indicating constant acceleration, negative slope indicating decreasing acceleration, and positive slope indicating increasing acceleration. The exact relation between power, torque, and acceleration also depends on the specific application, such as a vehicle like a motorbike. To determine this relation, data and curve-fitting techniques are needed.

- #1

Ketan Vadher

- 5

- 0

How will be the graph of varying acceleration and time if acceleration decreases?

Will it be a straight line with negative slope or any other shape?

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- #2

mfb

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- #3

RUber

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The question is, how is your acceleration changing? Do you have a formula for it?

- #4

insightful

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- #5

mfb

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Not if they are parking somewhere (a=0), or moving in traffic jams or whatever. That's the point, we have no idea what happens so it is impossible to know the acceleration.insightful said:Most cars (including drag racers) have maximum acceleration near t=0.

- #6

Ketan Vadher

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Thank you for such a response to my first question to Physics forum.

- #7

Ketan Vadher

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Today I get the graph of acceleration and time for my engine.

It will have a shape of paarabola x=-y^2 in first qudrent from Max acceleration to a=0.

Now I have a question regarding the reletion of power and acceleration & relation of torque and acceleration.

How to get relation for my engine. having max torque 18.6 N-m @2800 rpm.

how can I accelertion from power.

- #8

RUber

Homework Helper

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If you know torque, ##\tau##, mass, m, and you know the radius of the thing you are rotating, ##r##, you can relate torque to acceleration by:

##\tau = m r a ##

- #9

insightful

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I assume you mean to end up with an equation like:Ketan Vadher said:

Today I get the graph of acceleration and time for my engine.

It will have a shape of paarabola x=-y^2 in first qudrent from Max acceleration to a=0.

Now I have a question regarding the reletion of power and acceleration & relation of torque and acceleration.

How to get relation for my engine. having max torque 18.6 N-m @2800 rpm.

how can I accelertion from power.

a = a

For example, if initial acceleration were 1 m/s

a = 1 - 0.2236*sqrt(t)

Now, if you know the torque from the engine at a point in time, you can calculate the acceleration by calculating the force the wheels are applying to the vehicle, using F = ma. In practice, this is not possible because engine torque is not known at every point in time.

(Are we talking about a vehicle, like a motorbike?)

- #10

Ketan Vadher

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Thank you for response...insightful said:I assume you mean to end up with an equation like:

a = a_{0}- C*sqrt(t)

For example, if initial acceleration were 1 m/s^{2}and acceleration drops to 0 after 20 seconds, you have:

a = 1 - 0.2236*sqrt(t)

Now, if you know the torque from the engine at a point in time, you can calculate the acceleration by calculating the force the wheels are applying to the vehicle, using F = ma. In practice, this is not possible because engine torque is not known at every point in time.

(Are we talking about a vehicle, like a motorbike?)

But what is the C here?

How did you get the value of C=02236 here?

I am making an ATV car.

- #11

insightful

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C is a constant in the equation. It is found by putting my assumption in the example I gave that a=0 at t =20 s:Ketan Vadher said:But what is the C here?

How did you get the value of C=02236 here?

0 = 1 - C*sqrt(20) and solve for C.

The equation for acceleration is a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

Acceleration is directly proportional to time. This means that as time increases, acceleration also increases.

Acceleration is the rate of change of velocity with respect to time. This means that as acceleration increases, velocity also increases.

The direction of acceleration determines the direction of the change in velocity. If the acceleration is in the same direction as the velocity, the object will speed up. If the acceleration is in the opposite direction, the object will slow down.

The mass of an object has an inverse relationship with its acceleration. This means that as the mass of an object increases, its acceleration decreases. In other words, a heavier object requires more force to accelerate at the same rate as a lighter object.

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