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james123
A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If the mass is displaced by 10 mm from its equilibrium position and released, for the resulting vibration:Plot a graph of acceleration against displacement (x) (for values of x from x = –10 mm to x = +10 mm)
Hugely struggling to plot and draw this graph. Have been reading about a formula to give values for the acceleration but this formula is giving me numbers which seem way off.Formula: -(w^2 times displacement)
So, -25.81^2 x 0.1= -66.61561?Am I on the right track or miles off?? First post and any help is greatly appreciated!
Hugely struggling to plot and draw this graph. Have been reading about a formula to give values for the acceleration but this formula is giving me numbers which seem way off.Formula: -(w^2 times displacement)
So, -25.81^2 x 0.1= -66.61561?Am I on the right track or miles off?? First post and any help is greatly appreciated!