Relation between Hermite and associated Laguerre

  • Context: MHB 
  • Thread starter Thread starter Suvadip
  • Start date Start date
  • Tags Tags
    Laguerre Relation
Click For Summary
SUMMARY

The discussion focuses on proving the relationship between the Hermite polynomial H2n(x) and the associated Laguerre polynomial Ln(-1/2)(x²). The standard definition of the Laguerre polynomials is given by the formula $$\mathcal{L}_n(x)=\frac{e^x}{n!}\,\frac{d^n}{dx^n}[e^{-x}x^n]$$, while the Hermite polynomials are defined as $$\mathcal{H}_n(x)=(-1)^n\,e^{x^2}\,\frac{d^n}{dx^n}[e^{-x^2}]$$. The discussion suggests differentiating these definitions and considering power series expansions to compare coefficients, as well as exploring fractional integration as a potential approach.

PREREQUISITES
  • Understanding of Hermite polynomials and their definitions
  • Familiarity with associated Laguerre polynomials and their properties
  • Knowledge of differentiation techniques in calculus
  • Basic concepts of power series and their manipulation
NEXT STEPS
  • Study the properties of Hermite polynomials in detail
  • Explore the derivation and applications of associated Laguerre polynomials
  • Learn about fractional integration techniques and their applications
  • Practice differentiating power series and comparing coefficients
USEFUL FOR

Mathematicians, physicists, and students studying polynomial approximations, particularly those interested in the relationships between special functions in mathematical analysis.

Suvadip
Messages
68
Reaction score
0
Please help me in in proving the relation between H2n(x) and Ln(-1/2)(x2) where Hn(x) is the Hermite polynomial and Ln(-1/2)(x) is associated Laguerre polynomial.
 
Physics news on Phys.org
Hi Suvadip! :D

Are you familiar with "n-th derivative" definitions of the Hermite and Laguerre polynomials? The standard definition for the Laguerre polynomials is

$$\mathcal{L}_n(x)=\frac{e^x}{n!}\,\frac{d^n}{dx^n}[e^{-x}x^n]$$

although you do also occasionally come across the alternate form

$$ \mathcal{L}_n(x)=e^x\,\frac{d^n}{dx^n}[e^{-x}x^n]$$

The latter definition omits the scale factor $$1/{n!}\,$$ and so modifies the recurrence relations...On the other hand, the Hermite polynomials have the analogous definition:

$$\mathcal{H}_n(x)=(-1)^n\,e^{x^2}\,\frac{d^n}{dx^n}[e^{-x^2}]$$

You might try differentiating all 3 definitions - it's good practice! - and then see what happens... ;)

Also, you might consider expressing the terms to be n-differentiated as a power series, differentiating, multiplying back with the remainder of the function (in each respective function definition), and then compare the coefficients for all three results...Bets of luck! :D

- - - Updated - - -

Think fractional integration, that'd be my guess...
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 1 ·
Replies
1
Views
11K