Relationship between work and potential energy

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lzh
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Homework Statement


At time ti, the kinetic energy of a particle is
35.5 J and its potential energy is 8.16 J.At
some later time tf , its kinetic energy is 9.38 J.
If only conservative forces act on the parti-
cle, what is its potential energy tf ? Answer
in units of J.
If the potential energy at time tf is 6.95 J,
what is the work done by the nonconservative
forces acting on the particle? Answer in units
of J.

Homework Equations


W=F*displacement*cos(theta)

The Attempt at a Solution


For the first part of the question, because there were only conservative forces, the sum of kinetic and potential must be same for both ti and tf. And i know that i have the right answer for that. But for the second part, where force isn't conserved, that would not be the case:
I CANNOT take the sum of 35.5 and 8.16 and subtract 6.95 like i did for the first part.
I don't think i completely understand the concept here, so i'd appreciate any help.
 
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You're missing a relationship between work and energy. W = ______

Fill in the blank and you should have your answer. Hint (you're not looking for W = Fd)
 
work is kinetic energy here, right?
 
well, I started with 43.66J. But i don't know how much ends up being left.
 
wait... can this possibly be right?:
W=KE+PE
 
That's my line of thought...work done by non conservative forces= change in kinetic energy + change in potential energy
 
so does the answer to this part end up the same as first part of the question?
 
lzh said:
so does the answer to this part end up the same as first part of the question?
No. The initial mechanical energy,
(KE + PE)_initial, is 43.66J. The final mechanical energy, (KE + PE)_final, is 16.33J. The difference between the two represents the change in the total mechanical energy of the system , which is, as stated above, equal to the work done by the non-conservative forces.
 
would the change in mechanical energy be negative?
-27.33J in this case.
because +27.33J is wrong, according to my homework service
 
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Assuming you did the calculation right, the work should be negative.