1. The problem statement, all variables and given/known data A measuring cylinder contains 60cm3 of oil at 0 degrees celsius .When a piece of ice is dropped into the cylinder,it sank completely in oil and the oil level rose to 90 cm3 mark.When the ice melted the oil level came down to 87cm3 mark.The relative density of ice is (1)0.80 (2) 0.85 (3) 0.90 (4)0.95 (5)0.98 2. Relevant equations 3. The attempt at a solution I guess the volume of ice is 90-60=30cm3 and the relative density of ice can be given as = real weight of ice(mg) / apparent loss in weight in oil(mg-m'g)? mg would be 30*d*g,where d is the density of oil ,but how do I find its apparent weight in oil.I think it has something to do with the 87cm3 but I can't figure out what. Hope someone can help. Thanks in advance.