Relative velocity Question for a Ferryboat

[ahsila432]

Homework Statement

a ferryboat is travelling in a direction of 28 degrees north of east with a speed of 4.40 m/s relative to the water. A passenger is walking with a velocity of 2.02 m/s due east relative to the boat. What is the magnitude and direction of the velocity of the passenger with respect to the water. Give directional Angle to due east.

Relevant Equations

components, velocity equations

So far I have this:
vbwx= 4.40c0s(28) = 3.88496409

vbwy= 4.40sin28 = 2.065674876

vpwx= 4.4ocos28

vpwy= 4.40sin28 +2.02

Find Square root of vpx^2 + vpy^2 = 5.43?

Im confused as to whether we add the 2.02 to the sin28 or the cos28 though, did I do it right? Also, not sure how to find the angle at the end.

 

[PeroK]

Have you drawn a diagram of the two velocity vectors? The resultant velocity, magnitude and direction ought to be clear then.

 

[jbriggs444]

Homework Statement:: a ferryboat is traveling in a direction of 28 degrees north of east

This is a very poorly written question. It should say that the ferry boat has a heading 28 degrees north of east.

Heading and direction of travel are two very different things. Heading is which way the boat is pointed. This may not match the direction in which the boat moves with respect to the ground.