Relativistic centripetal force

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The discussion centers on the derivation and understanding of relativistic centripetal force, specifically the formula mv²/R[1-(v/c)²]³/². Participants debate the definition of "relativistic centripetal force" and whether it should be computed in the lab frame or the proper time frame of the moving particle. A hypothetical scenario involving Superman spinning a ball at 90% the speed of light is used to illustrate the complexities of measuring centripetal force and the impact of relativistic effects. The conversation highlights the importance of frame of reference in force measurements and the nuances of using geometric units versus conventional units in calculations. Ultimately, the discussion emphasizes the need for clarity in definitions and dimensional analysis when dealing with relativistic physics.
  • #31
Rotation?

HallsofIvy said:
Do you remember that relativistic effect happen along the direction of motion?

What relativistic effect are you referring to?
 
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  • #32
malawi_glenn said:
the constant is 0.3*B, where B is measured in T, and p in GeV/c

Where is my suggested typo?

That forumula is widely used in particle physics.
Sorry, I misunderstood the question. It seems to me that you have two separate questions, though, if I'm understanding it correctly this time.

1) How do you compute the momentum of a particle, given its observed radius of curvature in a magnetic field of known strength. (You've supplied your own answer to this one, it looks right though I haven't double checked it)

2) What is the force (i.e. dp/dt) on that particle in the lab frame?

The answer gamma m v^2 / r is correct here as well with these assumptions.

Note that you have to specify a frame in order to ask what the 3-force is. One of the advantages of 4-forces is that they are geometric, frame-independent objects , but the magnitude of the 3-force definitely depends on the frame in which it is measured.
 
  • #33
pervect said:
Sorry, I misunderstood the question. It seems to me that you have two separate questions, though, if I'm understanding it correctly this time.

1) How do you compute the momentum of a particle, given its observed radius of curvature in a magnetic field of known strength. (You've supplied your own answer to this one, it looks right though I haven't double checked it)

2) What is the force (i.e. dp/dt) on that particle in the lab frame?

The answer gamma m v^2 / r is correct here as well with these assumptions.

Note that you have to specify a frame in order to ask what the 3-force is. One of the advantages of 4-forces is that they are geometric, frame-independent objects , but the magnitude of the 3-force definitely depends on the frame in which it is measured.

The thing is that I don't have a question, I just wanted to add what I obtained to this discussion.

Maybe I should have written "I WAS trying to derive this forumula.." And then I played a bit, and also searched in some books etc to werify my steps, that's all. And I wanted to contribute with my "research" in this thread, where to OP seemed to find the expression i posted.
 
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