Relativistic Energy: Calculate Decay Product Kinetic Energy

Click For Summary

Homework Help Overview

The problem involves the decay of a radium isotope into a radon isotope and an alpha particle, focusing on calculating the total kinetic energy of the decay products. The subject area pertains to nuclear physics and energy conservation in radioactive decay.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the mass difference between the initial and final products, questioning how this relates to the kinetic energy of the decay products. There is also a mention of notation regarding the alpha particle.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the concept and seeking clarification. Some guidance has been offered regarding the mass difference, but no consensus or clear direction has emerged yet.

Contextual Notes

Participants have noted the importance of understanding this concept for solving related problems, indicating a potential learning constraint. There is also a reminder about the etiquette of waiting before posting again in the thread.

Aeighme
Messages
25
Reaction score
0

Homework Statement


A radium isotope decays to a radon isotope by emitting an α particle (a helium nucleus) according to the decay scheme 226Ra --> 222Rn + 4He. The masses of the atoms are 226.0254 u (226Ra), 222.0176 u (222Rn), and 4.0026 u (4He). What is the total kinetic energy of the decay products (in MeV)?

Homework Equations


E0=mc2
E=gamma*mc2
K=gamma*mc2-mc2
E=K+E0
1u=931.494 (MeV)/c2

The Attempt at a Solution


I really don't know what to do for this...
 
Physics news on Phys.org
Please help!
This concept is confusing for me and once I understand this, it will make the rest of my problems much easier to solve.
 
well...how much more massive is the input (radium), than the output (Radon and a Helium nucleus)...I'm not sure if you are confused by the notation, the 4He should be one helium nucleus with 4 nucleons.

~Lyuokdea
 
Aeighme said:
Please help!
This concept is confusing for me and once I understand this, it will make the rest of my problems much easier to solve.

calm down, wait more than 13minutes before bumping thread :-)
 
<< complete solution deleted by berkeman >>
 
Last edited by a moderator:

Similar threads

  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K