JesseM
Science Advisor
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Aether seems not to be describing an alternate theory at all, but just a different set of coordinate systems for describing a spacetime which obeys exactly the same laws as the one in SR. As in relativity, each observer can assign coordinates to events using a network of rulers and clocks, but instead of each observer synchronizing their clocks using the assumption that light travels at c in their own rest frame, only one observer synchronizes his clocks this way, and all other observers synchronize their clocks in such a way that their definition of simultaneity agrees with that preferred observer. If x and t are the coordinates assigned to an event by the preferred observer, then another observer moving at v along his access will assign the same event coordinates x' and t', with the coordinates related by the following "LET transformation":pmb_phy said:I wasn't suggesting anything by that question since I've yet to know what this theory you're speaking of is.
x' = (x - vt)/\sqrt{1 - v^2/c^2}
t' = t \sqrt{1 - v^2/c^2}
You can compare this with the Lorentz transformation:
x' = (x - vt)/\sqrt{1 - v^2/c^2}
t' = (t - vx/c^2) / \sqrt{1 - v^2/c^2}
Most people who use the term "Lorentz ether theory" would define the theory as saying there's an actual physical substance called "ether" and that the preferred observer should be at rest with respect to this ether, but Aether seems not to think this assumption is important, so he isn't making any new physical assumptions at all, he's just using a different set of coordinate systems. You can see, though, that if there was such a thing as ether, and all rulers moving relative to that ether shrunk by \sqrt{1 - v^2/c^2} while all clocks moving relative to that ether had their ticks extended by 1/\sqrt{1 - v^2/c^2}, then if all observers synchronized their clocks using the Einstein synchronization procedure, different observers' coordinate systems would be related by the Lorentz transform and there'd be no way to actually detect which frame was the ether's rest frame, so such a universe would be empirically equivalent to one where there is no ether but the laws of physics exhibit Lorentz-symmetry. I elaborated on this empirical equivalence a little more in the first two paragraphs of post #36.
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