[SOLVED] Released Spring 1. The problem statement, all variables and given/known data A piece of cheese with a mass of 1.35kg is placed on a vertical spring of negligible mass and a force constant k = 1600N/m that is compressed by a distance of 12.3cm . When the spring is released, how high does the cheese rise from this initial position? (The cheese and the spring are not attached.) 2. Relevant equations U1 = Ugrav1 + Uel1 U2 = Ugrav2 v1 = 0 v2 = 0 K1 = 0 K2 = 0 K1 + U1 = K2 + U2 --> Ugrav1 + Uel1 = Ugrav2 y1 = -.123m 3. The attempt at a solution (1.35kg)(9.81m/s^2)(-.123m) + 1/2k(-.123m)^2 = (1.35kg)(9.81m/s^2)h h = ((1.35kg)(9.81m/s^2)(-.123m) + 1/2(1600N/m)(-.123m)^2))/((1.35kg)(9.81m/s^s)) h = .80m it's incorrect and I'm not sure what I'm doing wrong, at the bottom position where the spring is compressed the initial position should be less than 0 correct? there's no velocity at the inital position and at the highest point there is no velocity or potential energy, only gravity should be acting on it correct? any help is greatly appreciated.