Removing units from Schrodingers equation

  • Thread starter Thread starter Avatrin
  • Start date Start date
  • Tags Tags
    Units
Click For Summary

Homework Help Overview

The discussion revolves around the application of the time-independent Schrödinger equation to model an electron in a one-dimensional finite square well. The original poster is attempting to create an animation of the wave function over time but encounters issues related to the scale of physical constants used in their calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster considers making their equations unitless to resolve issues with small values in their simulation. They express uncertainty about how to achieve this for certain constants.
  • Some participants suggest that the problem may lie with the step size in their numerical method rather than the units themselves.
  • There is a question regarding the appropriate step size for the simulation, with a suggestion of using picoseconds.
  • One participant mentions the use of reduced (atomic) units as a potential approach for the simulation.

Discussion Status

The discussion is ongoing, with participants exploring various aspects of the problem, including the dimensionality of the equations and the numerical methods employed. Some guidance has been offered regarding the use of atomic units and the importance of step size, but no consensus has been reached on the best approach to take.

Contextual Notes

The original poster is working under the constraints of a homework assignment, which may impose specific requirements on the formulation of the problem and the methods used. There is also a mention of the potential for the program to fail even after making the equations unitless.

Avatrin
Messages
242
Reaction score
6

Homework Statement


I am working on a problem regarding an electron in a one dimensional finite square well. I start off with [itex]\psi(x,0)[/itex] which is the symmetric solution to the time-independent Schrödinger equation for the well. Then I can use Euler's method to find [itex]\psi(x,t)[/itex] for the other values of t (for an animation), ie, I use:

[tex]\psi(x,t+dt) = \psi(x,t) + dt*\hat{H}\psi(x,t)[/tex]

Where [itex]\hat{H}[/itex] is the hamiltonian.

However, I am encountering a problem:
I think the values outside of the well are too small for Python; When I use the actual values for the speed of light, the electron mass and Planck's constant, I do not get an animation that makes sense; Actually, I do not get any animation at all. However, when I set all of the mentioned values equal to one, while the animaton still does not seem correct, it at least gives me an animation.

So, I am thinking of making my equations unitless. However, I do not know how. I have the following six constants:

[tex]\frac{V}{\hbar}\quad{\rm}\quad \frac{\hbar}{2m} \quad{\rm }\quad \kappa := \frac{\sqrt{-2mE}}{\hbar} \quad{\rm }\quad l:= \frac{\sqrt{2m(E+V)}}{\hbar}[/tex]
[tex]A=\frac{e^{\kappa a}\cos{la}}{\sqrt{a+1/\kappa}} \quad{\rm }\quad B=\frac{1}{\sqrt{a+1/\kappa}}[/tex]

Here a is half the width of the potential square well, and [itex]\hbar[/itex] is Planck's reduced constant. E is the particles energy and V is the depth of the potential well. Finally, m is the mass of an electron.

Homework Equations


[tex]-\frac{\hbar^2}{2m}\frac{d^2\psi}{dx^2} + V(x)\psi = i \hbar\frac{d\psi}{dt}[/tex]

[tex]-V<E<0[/tex]

The Attempt at a Solution


I can see the relation between the third of and fourth constants; [itex]\sqrt{\frac{-V}{E} - 1}[/itex]. The other constant, however, I am not certain how to make unitless.

Also, of course, there is no guarantee that my program will work when I make Schrödinger's equation and [itex]\psi(x,t)[/itex] unitless. So, I would love all advice that can potentially lead me to the solution.
 
Last edited:
Physics news on Phys.org
Last edited by a moderator:
You may be right. However, what should the step size be? In picoseconds?

Also, here is my animation when I changed the units to one ([itex]|\psi|^2[/itex]). Does it look right?
It changes into the same curve no matter what [itex]\psi(x,0)[/itex] is.

movie.gif
 
Last edited:

Similar threads

Replies
2
Views
2K
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
29
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K