How Do You Calculate the Couple in a Force-Couple System at Point O?

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To calculate the couple in a force-couple system at point O, first determine the resultant force from the three given forces. The moment caused by this resultant force at point O must be calculated to find the equivalent couple. This involves summing the moments of each force's components about the origin, taking care to account for their direction (clockwise or counterclockwise). The confusion often arises in identifying the correct distances to use for each force component when calculating these moments. Understanding these steps is crucial for correctly replacing the forces with an equivalent force-couple system.
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Homework Statement



I've attached an image. The question states:

Replace the three forces shown, with an equivalent force-couple system at point O(origin).

I've got a little ways, but I am stuck at the couple. I don't know how to use the distance in the couple. Need to know what distance to use, and from where.

Homework Equations



R = Fx + Fy

C = Mo = ra/o x Fa + rb/o x Fb + rc/o x Fc(is this correct, or do I use x and y?)---this is the part where I'm stuck.

magnitude C = sqrt(Cx^2 + Cy^2)

The Attempt at a Solution



Fx = 200cos60 + 300cos45 + 250cos30 = 528.6 i

Fy = 200sin60 + 300sin45 - 250sin30 = 260.3 j

R = 528.6 i + 260.3 j

C = Mo = ?

Am I correct up to this point too?

View attachment sample exam1.bmp
 
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Bradracer18 said:

Homework Statement



I've attached an image. The question states:

Replace the three forces shown, with an equivalent force-couple system at point O(origin).

I've got a little ways, but I am stuck at the couple. I don't know how to use the distance in the couple. Need to know what distance to use, and from where.

Formally, you should first find the resultant of the three forces. To find the couple, you first have to find the moment caused by the resultant force at point O, and then replace that moment with an equivalent couple.
 
Ok, I did find the resultant(R).

And, to find the couple, don't I just find the moment(at the origin)?

Here goes...but this is where I get confused.

528.6(9) + 260.3(30)...i have no clue, I know this isn't right.

Any way you could show me like part of how to do it? So I get the concept?
 
Bradracer18 said:
Ok, I did find the resultant(R).

And, to find the couple, don't I just find the moment(at the origin)?

Here goes...but this is where I get confused.

528.6(9) + 260.3(30)...i have no clue, I know this isn't right.

Any way you could show me like part of how to do it? So I get the concept?
you've got the correct components of the resultant force at the origin. But now you must sum moments of each horizontal component of each force about the origin, and sum moments of each vertical component of each force about the origin, and add them together to get the couple about the origin. Watch your plus and minus signs (clockwise vs. counterclockwise).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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