A 120-V circuit has a circuit breaker rated to trip (to create an open circuit) at 15 A. How many 300-ohm resistors could be connected in parallel without tripping the breaker? Given that, V= 120V, I = 15A, R= 300 ohm. Let the total resistance without tripping the breaker = Rp Now 1/Rp = 1/R + 1/ R + ………n times. = n/R Therefore Rp = R/n Or n = R/ Rp But Rp = 120/15 = 8 Therefore n = 300/8 = 37.5=38 Is this correct?