Resolving Vector Forces with Measured Angles | Fz and FH Components"

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ur5pointos2sl
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The question states:
Use the measured angles to resolve each of the forces exerted by the strings into a z-component(Fz) and a horizontal component(FH).

Fz = F cos Theta
FH = F cos Theta

Given angles and forces:

30 deg. 270 N
135 deg. 170 N
240 deg. 260 N

I am a little confused about the problem and what exactly its asking for.

I will just show you my attempt for 30 deg. and see if it is the correct approach.


angle 30 deg
force 270 N
Fz = F cos Theta = 135
FH = F cos Theta = 234

Is this what they mean by a Z component and horizontal?
 
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Resolving a vector means splitting it up into it's components. What you have is correct except you have [tex]cos\Theta[/tex] in both of them. I assume you meant the two equations to be
[tex]F_z = Fsin\theta[/tex]
[tex]F_x = Fcos\theta[/tex]
You got the right answers so I guess you just meant sin.
 
Jebus_Chris said:
Resolving a vector means splitting it up into it's components. What you have is correct except you have [tex]cos\Theta[/tex] in both of them. I assume you meant the two equations to be
[tex]F_z = Fsin\theta[/tex]
[tex]F_x = Fcos\theta[/tex]
You got the right answers so I guess you just meant sin.

Ok thank you. Now that I have done this there is a second part to the question.

Resolve FH into x- and y- components, Fx and Fy.

Fx=FH cos Phi
Fy=FH sin Phi

How would I use the equations since its Phi instead of Theta. This is a 3-D problem just to make you aware. Therefore, Phi is the angle between FH and the x axis. I am not sure how to get Phi.