Resolving Vector W: Tips & Tricks for Uniform Circular Motion

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Homework Help Overview

The discussion revolves around resolving vector W in the context of a particle undergoing uniform circular motion. Participants are exploring the relationship between tension, weight, and the components of vector W, particularly focusing on the angles involved in the resolution of these vectors.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss creating a right triangle to analyze vector W and its components. There are questions about the appropriate axes to use for resolving the vector and the angles involved in the resolution. Some participants express confusion about the relationship between vector W and its components, particularly regarding the angle with the x-axis.

Discussion Status

The discussion is active, with participants offering suggestions on how to visualize the problem through diagrams and right triangles. There is an ongoing exploration of the coordinate system that would best facilitate the resolution of vector W, with no clear consensus yet on the optimal approach.

Contextual Notes

Participants are navigating potential assumptions about the angles and directions of the axes in their diagrams, which may affect their understanding of the vector components. There is a mention of the need to clarify the orientation of the axes in relation to the forces involved.

sphyics
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1. A particle is performing uniform circular motion
ucm1.jpg


the necessary centripetal force is provided by T2 -mgcos(theta) ****** no problem :)

2 Now the problem
ucm2.jpg


how to resolve vector W in this case.

i'm confused :( how to resolve the vector. (confused in picking the anlge between the vector and the component)

pls help me by providing some hints pls..
 
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Extend the line along W until it intersects the horizontal axis. You have just created a right triangle. One right side is W, one right side is the segment of the horizontal axis and the hypotenuse is T1. Can you find the component of W along T1?
 
kuruman said:
Extend the line along W until it intersects the horizontal axis. You have just created a right triangle. One right side is W, one right side is the segment of the horizontal axis and the hypotenuse is T1. Can you find the component of W along T1?

my aim is to find a component of W which balances tension (T1) of the string and another component which tries to decrease the velocity of the object in circular motion in first quadrant.
 
I understand your aim. As you know, to describe the components of a vector, you need two perpendicular axes. What do you think these axes should be in this case?
 
ucmpro.jpg


or

ucmpro1.jpg


but in both cases the angle between the vector w and its x componet is not congurent to (theta) {i think so}
 
sphyics said:
... but in both cases the angle between the vector w and its x componet is not congurent to (theta) {i think so}

Your diagrams are fine, but you did not tell which way your axes point. In what direction is x?
 
ucmpro1-1.jpg
 
In that case, the weight has zero x-component and -mg for the y-component. What would happen if you chose the x-axis along T1 and the y-axis perpendicular to it, up and to the left? Note that this is a very convenient coordinate system because the centripetal acceleration and tension are along x. Of course you will have to find the x and y components for the weight in the system of axes.
 

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