Resonance frequency in second-order system

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SUMMARY

The discussion focuses on the resonant frequency of a second-order system characterized by the transfer function G(s) = 1/(s² + 2ζωₙs + ωₙ²). The peak frequency, ωₚₑₐₖ, is derived as ωₚₑₐₖ = ωₙ√(1 - 2ζ²), indicating that ωₚₑₐₖ is non-negative for damping ratios ζ ≤ √2/2. For damping ratios greater than √2/2 but less than 1, the system does not resonate at a specific frequency, leading to confusion regarding its oscillatory behavior. Clarification is provided that for ζ > 1/√2, ωₚₑₐₖ becomes imaginary, indicating non-existence.

PREREQUISITES
  • Understanding of second-order systems and transfer functions
  • Familiarity with damping ratios (ζ) and natural frequency (ωₙ)
  • Knowledge of frequency response analysis
  • Basic concepts of oscillation and resonance in control systems
NEXT STEPS
  • Study the implications of damping ratios on system behavior in control theory
  • Learn about the frequency response function and its maximization techniques
  • Explore the characteristics of underdamped, critically damped, and overdamped systems
  • Investigate the concept of imaginary frequencies in control systems
USEFUL FOR

Control engineers, system analysts, and students studying dynamic systems who seek to understand the effects of damping on resonance in second-order systems.

refrigerator
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Suppose we have a second-order system with the following transfer function:

G(s)= \frac{1}{s^{2} + 2ζω_{n}s +ω_{n}^{2}}

To figure out its resonant frequency, obtain its frequency response function and then maximize it with respect to ω. You get:

ω_{peak} = ω_{n}\sqrt{1-2ζ^{2}}

So it appears that ω_{peak} ≥ 0 for ζ ≤ \frac{\sqrt{2}}{2}

But what happens if the damping ratio is greater than that, but still less than 1? Then does the system simply oscillate but not resonate at any particular frequency? This bit confuses me. I'd appreciate any help in clearing this up.

Thank you in advance,

Refrigerator
 
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hi refrigerator! :smile:
refrigerator said:
So it appears that ω_{peak} ≥ 0 for ζ ≤ \frac{\sqrt{2}}{2}

nooo …

peak ≥ 0" isn't really saying anything, is it? :wink:

(and if ζ > 1/√2, then ωpeak is imaginary … ie, it doesn't exist :wink:)
 
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