DaveE
Science Advisor
Gold Member
2024 Award
- 4,415
- 4,071
According to me, yes, because the roots are complex. It is a simple definition, probably not satisfying to many because there isn't any gain peaking and little overshoot in the step response. You are free to choose your own threshold. How high does Q have to be to be resonant? How do you avoid a somewhat arbitrary choice?LvW said:Example (question): Is there any resonance effect with a second order Butterworth low pass (one complex pole pair) with a phase shift of 90deg at w=wp?
https://2n3904blog.com/butterworth-filter/