A long tube contains air at a pressure of 1.00 atm and a temperature of 77.0 degrees celsius. The tube is open at one end and closed at the other by a movable piston. A tuning fork near the open end is vibrating with a frequency of 500 Hz. Resonance is produced when the piston is at distances 18.0, 55.5, and 93.0 cm from the open end.
These data show that a displacement antinode is slightly outside of the open end of the tube. How far outside is it?
f1 = v/4L
f1 = v/2L
The Attempt at a Solution
I have tried this a couple times, and got .008m. I use mastering physics, and don't have many attempts left, because apparently my answer is wrong. I can't figure out what it is I am doing incorrectly.