Rest energy and Kinetic Energy of a Photon - velocity?

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SUMMARY

The discussion centers on the relationship between the kinetic energy and rest energy of a photon, specifically addressing the scenario where the kinetic energy equals the rest energy. The correct velocity of the photon is determined to be sqrt(3)/2 x c, contrary to the initial assumption that it would be sqrt(2) x c. The confusion arises from the misapplication of classical kinetic energy equations in the context of relativistic physics, where total energy is defined as E = KE + mc², and the kinetic energy is interpreted as total energy minus rest energy.

PREREQUISITES
  • Understanding of relativistic energy equations, specifically E = mc²
  • Familiarity with the concept of kinetic energy in the context of special relativity
  • Knowledge of the speed of light (c) and its implications in physics
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of relativistic energy equations, focusing on E = mc² and E = KE + mc²
  • Learn about the implications of mass-energy equivalence in special relativity
  • Explore the concept of relativistic momentum and its relationship to energy
  • Investigate the differences between classical and relativistic kinetic energy formulations
USEFUL FOR

Students studying physics, particularly those focusing on relativity, educators teaching advanced physics concepts, and anyone interested in the nuances of energy and motion in the context of special relativity.

max8404
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Homework Statement



Thanks for everyone that helped me with the physics questions! I had my physics 2 final today and got a 94! There was a question that I could not figure out for a long time. It goes like this.

What would the velocity of the photon be if the Kinetic energy of the photon equals the rest energy of the photon? Express v in terms of c and anything else. Luckily, the question was a multiple choice, and the correct answer (which I guessed) was sqrt(3)/2 x c

I still cannot figure out why this is true.


Homework Equations



K=1/2mv^2 --> I assume this is the right equation to use...
Er=mc^2

The Attempt at a Solution



Equaling the two would give you:

1/2mv^2=mc^2

v^2=2c^2
v=sqrt(2) x c

This is obviously not true since you can't go faster than the speed of light. Can someone explain to me how the answer is sqrt(3)/2 x c and why I am getting this thing wrong? Am I using the right Kinetic Energy equation??

Thanks!
 
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congratulations!

Hi max8404! Many congratulations! :biggrin:
max8404 said:
What would the velocity of the photon be if the Kinetic energy of the photon equals the rest energy of the photon? Express v in terms of c and anything else. Luckily, the question was a multiple choice, and the correct answer (which I guessed) was sqrt(3)/2 x c

Homework Equations



K=1/2mv^2 --> I assume this is the right equation to use...
… why I am getting this thing wrong? Am I using the right Kinetic Energy equation??

oooh, I wish examiners wouldn't use "kinetic energy" in relativity :cry:

they just mean total energy minus rest energy :rolleyes:

so 2m = m/√(1 - v2/c2), so 1 - v2/c2 = 1/4 :wink:
 


tiny-tim said:
Hi max8404! Many congratulations! :biggrin:


oooh, I wish examiners wouldn't use "kinetic energy" in relativity :cry:

they just mean total energy minus rest energy :rolleyes:

so 2m = m/√(1 - v2/c2), so 1 - v2/c2 = 1/4 :wink:

Hey Tiny Tim, thanks for your response, but I doon't quite get it. I understand the equation,
E=KE+mc^2, but in this case, what would E be? Or am I once again looking at it the wrong way?

Thanks!
 
E is the total energy (or relativistic energy), mc2/√(1 - v2/c2) :smile:
 
tiny-tim said:
E is the total energy (or relativistic energy), mc2/√(1 - v2/c2) :smile:

duh. thanks a lot! I got it now! :)
 
I have a big problem with a photon's velocity being less than c.
 

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