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- Homework Statement
- During a period of time, a 100kg cart’s KE doubles. During that time, friction does -500J of work and the vehicle that is pulling the cart does 5000J of work on the cart. This scenario occurred on level ground. Find the final kinetic energy of the cart and the cart’s initial velocity

- Relevant Equations
- Worknc + KEinitial = KEfinal +Workfriction

Energy(initial) = Energy(final)

-I think there’s a equation for the initial velocity, but I’m not quite sure

Here's my list of variables and things to account for:

m=100kg

Wnc=5000J

Wfriction=-500J

-Kinetic energy will be doubled (though I don't know how that plays into it exactly)

-I don't think there's any PE because it's on level ground

My idea of what the equation might be:

Wnc +1/2mv^2initial = 2(1/2mv^2final) + Wfriction

5000+ 1/2(100)v^2 = 2(1/2(100)v^2) + 500

-From here, I'm not quite sure how to find both velocities and subsequently the final KE

m=100kg

Wnc=5000J

Wfriction=-500J

-Kinetic energy will be doubled (though I don't know how that plays into it exactly)

-I don't think there's any PE because it's on level ground

My idea of what the equation might be:

Wnc +1/2mv^2initial = 2(1/2mv^2final) + Wfriction

5000+ 1/2(100)v^2 = 2(1/2(100)v^2) + 500

-From here, I'm not quite sure how to find both velocities and subsequently the final KE

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