1. The problem statement, all variables and given/known data A 0.30-kg mass attached to the end of a string swings in a vertical circle (R = 1.6 m), as shown. At an instant when θ = 50°, the tension in the string is 8.0 N. What is the magnitude of the resultant force on the mass at this instant? http://www.flickr.com/photos/89533422@N08/8142258633/in/photostream/lightbox/ 2. Relevant equations m*centripetal acceleration=m*v^2/r mg basic trig 3. The attempt at a solution I've figured out mg = 2.94 N mg sin 50 = 2.25 N (which acts opposite of the direction of the mass) mg cos 50 =1.89 N (the tension due to gravity) 8-1.89 = 6.11 N (the tension due to motion of the mass) 8=0.3*v^2/1.6 (v=5.71 m/s) -2.25=0.3*a (a=-7.5 m/s^2) I'm not 100% on the last 2 But I still don't know what the resultant force is? Or even what force they are referring to. If anyone can help it would be greatly appreciated!