Retraction Math Help: Does a Group Exist with Trivial Retracts?

  • Context: Graduate 
  • Thread starter Thread starter Oxymoron
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the existence of a group G that is not simple and has only trivial retracts. A subgroup H of G is defined as a retract if there exists a homomorphism q: G → H such that q(h) = h for all h in H. The participants explore the implications of this definition, particularly focusing on the semi-direct product K ⋊ H and its properties. They conclude that groups such as Z/p^n for primes p and n > 1, as well as Z4, exhibit the desired characteristics, but they also clarify that Z4 does not have non-trivial retracts.

PREREQUISITES
  • Understanding of group theory concepts, specifically retracts and homomorphisms.
  • Familiarity with semi-direct products and their properties in group theory.
  • Knowledge of cyclic groups and their subgroup structures, particularly Z/p^n.
  • Basic understanding of normal subgroups and their significance in group theory.
NEXT STEPS
  • Research the properties of semi-direct products in group theory.
  • Study the classification of abelian groups and their subgroup structures.
  • Explore the implications of retracts in non-simple groups.
  • Examine the relationships between homomorphisms and generators in cyclic groups.
USEFUL FOR

Mathematicians, particularly those specializing in abstract algebra, group theorists, and students studying group theory concepts related to retracts and homomorphisms.

  • #31
Any direct sum of denumerably many groups will have (at least) denumerably many retracts, and any direct product of denumerably many groups will have uncountably many retracts. The projection maps are retractions.
 
Physics news on Phys.org
  • #32
Any direct sum of denumerably many groups will have (at least) denumerably many retracts
That "at least" is worrying me. Any countably infinite direct sum of (nontrivial) groups has uncountably many retracts; one for every subset of the index set. (and possibly more) I suspect that an abelian group cannot have exactly countably infinite retracts... and if I'm wrong, it will still be a tricky business finding an example.
 
  • #33
Hurkyl said:
That "at least" is worrying me. Any countably infinite direct sum of (nontrivial) groups has uncountably many retracts; one for every subset of the index set.
Yeah, you're right.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 7 ·
Replies
7
Views
3K