Rewrite in logarithmic form: e^(-1) = c

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Discussion Overview

The discussion revolves around rewriting the equation \( e^{-1} = c \) in logarithmic form. Participants explore the relationship between exponential and logarithmic expressions, touching on foundational concepts of logarithms.

Discussion Character

  • Technical explanation, Conceptual clarification

Main Points Raised

  • One participant rewrites the equation using natural logarithms, stating that \( \ln(e^{-1}) = \ln(c) \) leads to \( -1 = \ln(c) \).
  • Another participant questions the understanding of logarithms by the original poster, suggesting that they may not be familiar with the concept if they are posting multiple logarithm problems.
  • A definition of logarithms is provided, indicating that the expression \( y = a^x \) is equivalent to \( \log_a(y) = x \).

Areas of Agreement / Disagreement

Participants do not reach a consensus on the original poster's understanding of logarithms, with some expressing concern over their grasp of the topic.

Contextual Notes

The discussion highlights potential gaps in foundational knowledge regarding logarithms, but does not resolve the original poster's understanding or the correctness of the mathematical steps presented.

Vi Nguyen
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Rewrite in logarithmic form:

e^(-1) = c
 
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$$\ln\left(e^{-1}\right)=\ln(c)$$

$$-1=\ln(c)$$
 
thanks
 
You have posted a number of logarithm problems without, apparently, know what a "logarithm" is! If you are not taking a class that involves logarithms, where are you getting these problems?

$y= a^x$ is equivalent to $log_a(y)= x$.
 
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