MHB Rewrite in logarithmic form: e^(-1) = c

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The equation e^(-1) = c can be rewritten in logarithmic form as ln(e^(-1)) = ln(c), which simplifies to -1 = ln(c). The discussion highlights a misunderstanding of logarithms, questioning the source of the logarithm problems being posed. It emphasizes the equivalence between exponential and logarithmic forms, stating that if y = a^x, then log_a(y) = x. Understanding these concepts is crucial for solving logarithmic equations effectively. The conversation underscores the importance of grasping the fundamentals of logarithms for accurate problem-solving.
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Rewrite in logarithmic form:

e^(-1) = c
 
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$$\ln\left(e^{-1}\right)=\ln(c)$$

$$-1=\ln(c)$$
 
thanks
 
You have posted a number of logarithm problems without, apparently, know what a "logarithm" is! If you are not taking a class that involves logarithms, where are you getting these problems?

$y= a^x$ is equivalent to $log_a(y)= x$.
 
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Thread 'Leibniz Rule Videos on Digital-University'

Good morning I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...
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