# Rewrite in logarithmic form: e^(-1) = c

• MHB
• Vi Nguyen
In summary, the logarithmic form of e^(-1) is ln(c) = -1, where ln represents the natural logarithm and c is the base of the logarithm. To solve for c, we can take the antilogarithm of both sides, which means raising both sides to the power of e. This gives us c = e^(-1). The exponential form of e^(-1) = c is c = e^(-1). The value of c represents the base of the logarithm, which is being raised to the power of -1 to equal e. The natural logarithm is commonly used in scientific calculations to solve exponential equations, model natural phenomena, and analyze data with nonlinear relationships. It is
Vi Nguyen
Rewrite in logarithmic form:

e^(-1) = c

$$\displaystyle \ln\left(e^{-1}\right)=\ln(c)$$

$$\displaystyle -1=\ln(c)$$

thanks

You have posted a number of logarithm problems without, apparently, know what a "logarithm" is! If you are not taking a class that involves logarithms, where are you getting these problems?

$y= a^x$ is equivalent to $log_a(y)= x$.

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## 1. What is the logarithmic form of e^(-1) = c?

The logarithmic form of e^(-1) = c is ln(c) = -1.

## 2. How do you solve for c in the equation e^(-1) = c?

To solve for c, take the natural logarithm of both sides: ln(e^(-1)) = ln(c). This simplifies to ln(c) = -1. Then, use the inverse property of logarithms to rewrite the equation as c = e^(-1).

## 3. What does the value of c represent in the equation e^(-1) = c?

The value of c represents the result of raising e to the power of -1, which is approximately 0.3679.

## 4. Can you rewrite the equation e^(-1) = c in exponential form?

Yes, the exponential form of e^(-1) = c is c = e^(-1).

## 5. What is the significance of e in the equation e^(-1) = c?

The number e, also known as Euler's number, is a mathematical constant that is approximately equal to 2.71828. It is commonly used in logarithmic and exponential functions, and in this equation, it represents the base of the natural logarithm.

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