- #1

Nousher Ahmed

- 12

- 0

-10<x-3<10

But can rewrite |x-3|+|x+1|+|x|<10 in the following way?

-10<x-3+x+1+x<10.

If we cannot, will anybody please explain why we cannot?

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- MHB
- Thread starter Nousher Ahmed
- Start date

- #1

Nousher Ahmed

- 12

- 0

-10<x-3<10

But can rewrite |x-3|+|x+1|+|x|<10 in the following way?

-10<x-3+x+1+x<10.

If we cannot, will anybody please explain why we cannot?

- #2

romsek

- 30

- 0

You can write it as a union of such rules though.

In this case it appears to be

$(x < -\dfrac 8 3) \cup (4 < x)$

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