Solving a 5.4 Earthquake Aftershock: Round to 1 Decimal Place

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SUMMARY

The discussion focuses on calculating the magnitude of an aftershock following a 5.4 magnitude earthquake, which is 39 times less intense. Using the formula M=log(I/I0), participants are guided to first compute the intensity (I) of the original quake, then divide that intensity by 39 to find the aftershock's intensity. Finally, the magnitude of the aftershock can be derived by applying the logarithmic difference between the two intensities. The correct approach leads to a magnitude of approximately 4.6 for the aftershock when rounded to one decimal place.

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  • Understanding of logarithmic functions and their properties
  • Familiarity with earthquake magnitude scales
  • Basic knowledge of intensity calculations in seismology
  • Ability to perform mathematical operations involving logarithms
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  • Study the Richter scale and its application in measuring earthquake magnitudes
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Students in seismology, mathematicians interested in logarithmic applications, and professionals involved in earthquake research and analysis will benefit from this discussion.

JasSingh96
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Can someone please solve this . I have been trying to solve this from last 2 days.
1. Question
  1. An earthquake with a magnitude of 5.4 is 39 times as intense as an aftershock that occurs five hours later. What is the magnitude of the aftershock? Round your answer to one decimal place.
2. Formula Given in Text Book.
M=log(I/I0)

  • M is the magnitude
    [*]I is the intensity of the earthquake
    [*]I0 is the intensity of an earthquake with a magnitude of 0

formula for richter scale.PNG


Thanks
 

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Use the magnitude to compute the I of the original quake.

Divide that I by 39 to find the intensity of the aftershock.

Compute the mahnitude of the aftershock.
 
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If the intensity are ##I_1,~I_2,## then their magnitudes' difference can be done with ##M_1-M_2=\ln\frac{I_1}{I_0}-\ln\frac{I_2}{I_0}## right? With the information you got, try to have some attempts on it .
 
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