Riemann Zeta Function and Pi in Infinite Series

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Discussion Overview

The discussion revolves around the properties of infinite series involving the Riemann Zeta function and their convergence to values related to π. Participants explore the implications of using even and odd natural numbers as exponents in these series.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant proposes that the series \(\sum_{n=1}^{\infty} \frac{1}{n^\phi}\) converges to a rational multiple of π when \(\phi\) is an even natural number.
  • Another participant states that the series \(\sum_{n=1}^{\infty} \frac{1}{n^\alpha}\) converges to the Riemann Zeta function evaluated at \(\alpha\), where \(\alpha\) is also an even natural number.
  • A later reply suggests that the only difference between the two series is the change from \(\phi\) to \(\alpha\), questioning if there should be a distinction between them.
  • One participant mentions that the first series converges to \(\zeta(\phi)\) and relates it to a rational function of π, while noting that if \(\alpha\) is odd, the value is simply \(\zeta(\alpha)\), which is described as mysterious and not well understood.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between the two series and the nature of their convergence. There is no consensus on whether there is a significant difference between the two series based on the parity of the exponents.

Contextual Notes

Participants mention the extension of the Riemann Zeta function to complex exponents through analytic continuation, but the implications of this process remain unresolved in the discussion.

Who May Find This Useful

This discussion may be of interest to those studying mathematical series, the Riemann Zeta function, or related topics in advanced mathematics and physics.

Kevin_Axion
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I was playing around with an infinite series recently and I noticed something peculiar, I was hoping somebody could clarify something for me.

Suppose we have an infinite series of the form:

\sum^_{n = 1}^{\infty} 1/n^\phi

where \phi is some even natural number, it appears that it is always convergent to a rational multiple of \pi.

Now if we take this series and change it slightly:

\sum^_{n = 1}^{\infty} 1/n^\alpha

where \alpha is some even natural number, it appears that it is always convergent to the Riemann Zeta Function evaluated at \alpha i.e. \zeta(\alpha).

Can someone explain the relationship expressed in these infinite series?

EDIT: What's wrong with my LaTeX for the infinite series?
 
Last edited:
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I don't see what the difference between the two series you posted is, except changing phi to alpha. The LaTeX is perhaps not working because you wrote an extra ^ after the \sum, which shouldn't be there.

The reason that the sum "converges" to the Riemann Zeta function is that for integer exponents that series is the definition of the Riemann Zeta function. It is then extended to arbitrary complex exponents by analytic continuation. If you compute \zeta(2n) for n a positive integer, you would find it is a multiple of \pi to some power.
 
Here's the post with fixed LaTeX...
Maybe there should be something different between the first and two series?

Kevin_Axion said:
I was playing around with an infinite series recently and I noticed something peculiar, I was hoping somebody could clarify something for me.

Suppose we have an infinite series of the form:

\sum_{n = 1}^{\infty} \frac{1}{n^\phi}

where \phi is some even natural number, it appears that it is always convergent to a rational multiple of \pi.

Now if we take this series and change it slightly:

\sum_{n = 1}^{\infty} \frac{1}{n^\alpha}

where \alpha is some even natural number, it appears that it is always convergent to the Riemann Zeta Function evaluated at \alpha i.e. \zeta(\alpha).

Can someone explain the relationship expressed in these infinite series?

EDIT: What's wrong with my LaTeX for the infinite series?
 
Very cool, the only difference I made was that the exponent is even in one and odd in the other.
 
Kevin_Axion said:
Very cool, the only difference I made was that the exponent is even in one and odd in the other.

Ah, then you probably made a typo :smile:

Anyway, the first series will also converge to \zeta(\phi), and this will have a nice characterization as a rational function of pi.
If alpha is odd, then all we know is that the value is \zeta(\alpha). These values are very mysterious and not well understood. For example, \zeta(3) is called Apery's constant and shows up in some physics problems.

But you'll see more of this in your future math major! :biggrin:
 
Haha! Engineering :approve:!
 

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