- #1

- 288

- 6

- I
- Thread starter e2m2a
- Start date

- #1

- 288

- 6

- #2

mfb

Mentor

- 35,125

- 11,362

- #3

mathman

Science Advisor

- 7,889

- 460

- #4

- 288

- 6

ok. That's what I wanted to know.

- #5

- 10

- 0

Would it be relevant to find a formula wich generates them all with only two variables..?

- #6

mfb

Mentor

- 35,125

- 11,362

(3,4,5) is generated by n=1, m=2, and (8,6,10) is generated by n=1, m=3, but (9,12,15) is not covered as 15 cannot be written as the sum of two squares.

It is trivial to extend the formula to cover all multiples, just add a common factor k to all three lengths. Then you get some triplets with more than one set of integers, but you cover all triplets at least once.

- Last Post

- Replies
- 5

- Views
- 5K

- Last Post

- Replies
- 2

- Views
- 787

- Replies
- 10

- Views
- 844

- Replies
- 6

- Views
- 602

- Last Post

- Replies
- 8

- Views
- 2K

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 4

- Views
- 315

- Last Post

- Replies
- 3

- Views
- 893

- Last Post

- Replies
- 10

- Views
- 32K

- Last Post

- Replies
- 5

- Views
- 2K