A uniform rectangular tile drops without spinning until its corners reach positions
(0; 0; 0); (2a; 0; 0); (2a; 2b; 0); (0; 2b; 0), when it strikes the top of a vertical pole at a
point very close to the (0; 0; 0) corner. Just before impact the velocity of the tile was
(0; 0;u). Assuming that the tile does not break, and that the impact is elastic (i.e.
the kinetic energy of the tile is conserved), find immediately after impact
(a) the velocity of its centre;
(b) the angular momentum about its centre;
(c) its angular velocity.
Show that the velocity of the corner at (0; 0; 0) becomes (0; 0;+u) immediately after
Inertia tensors of the rigid body involved, all standard mechanics equations.
The Attempt at a Solution
I honestly have no idea how to approach this...all i can write down is the initial KE = final KE...