Ring launcher conceptual question

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SUMMARY

The discussion centers on the behavior of an aluminum ring in a ring launcher when an alternating current (AC) is applied to the coil. The aluminum ring flies upward due to the induced electromotive force (emf) generating a current that opposes the magnetic field from the launcher, as described by Lenz's Law. In contrast, a split ring does not generate any current because it is not a closed loop, resulting in zero magnetic flux and no upward motion.

PREREQUISITES
  • Understanding of Lenz's Law and electromagnetic induction
  • Familiarity with alternating current (AC) circuits
  • Knowledge of magnetic flux concepts
  • Basic principles of electromotive force (emf)
NEXT STEPS
  • Study the principles of electromagnetic induction in depth
  • Learn about the applications of Lenz's Law in real-world scenarios
  • Explore the differences between closed and open circuits in electromagnetic contexts
  • Investigate the effects of varying frequencies of AC on induced currents
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in the principles of electromagnetism and their practical applications in devices like ring launchers.

Physicsnoob24
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Homework Statement


When an aluminum ring is placed on ring launcher so that it surrounds the coil, it flies upward when a AC current is applied to the coil. This does not occur when the intact ring is replaced by a split ring (see below). Explain this in 3 sentences or less. Feel free to use as many diagrams and equations as you need in your explanation. [Warning: The standard explanation of this lacks any mention of an essential feature.]

Homework Equations

The Attempt at a Solution


This is my rationalization as to why this occurs:
When the AC-current was turned on, the emf generated in the Aluminum ring led to a current in it, which according to Lenz's Law, has to be in a direction such that its field cancels the one due to the ring launcher: so it is opposite in direction and since opposite currents repel, the ring flies off. When a split ring is used, since it is not a closed loop, there is no flux going through it is 0. Hence, there is no emf or current generated: so it does not fly off.

Did this go beyond the "standard explanation", as my Professor puts it? Or did I miss something "essential?"
I have uploaded a picture of the figure (if it helps at all). I can only receive partial credit if my Professor isn't completely satisfied with the answer so if I'm missing something, I would greatly appreciate it if anyone could help steer me in the right direction. Thank you so much!
 

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Currents do not repel. There is something else that repels something.
Physicsnoob24 said:
When a split ring is used, since it is not a closed loop, there is no flux going through it is 0.
Going through what?
Physicsnoob24 said:
Hence, there is no emf or current generated
One of them is generated.

I don't know what exactly your prof means, but here is a question you did not answer: how does the ring know in which direction it has to go?
 

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