"Robustness" of Nielsen-Thurston Classification

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The discussion centers on the robustness of the Nielsen-Thurston classification in the context of topological spaces with universal covers. It establishes that for a homeomorphism \( h: X \rightarrow X \), the induced automorphism \( \tilde h: \tilde X \rightarrow \tilde X \) is indeed a homeomorphism. Additionally, the conversation touches on the preservation of classes in the Nielsen-Thurston framework, specifically questioning whether isotopy conditions for homeomorphisms imply similar isotopy results for their isotopic counterparts.

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WWGD
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Hi all,

Let X be a nice-enough topological space so that it admits a universal cover ## \tilde X ##

When does a homeomorphism ## h: X \rightarrow X ## give rise to a homeomorphism

of the universal cover to itself, i.e., we have ## p: \tilde X \rightarrow X ## , then, by

lifting properties this gives rise to (after choosing a specific sheet in the cover) to an

automorphism ## \tilde h : \tilde X \rightarrow \tilde X ## satisfying ## p \tilde h =hp ## ( I wish

I knew how to draw the diagram in here). Question: is ## \tilde h ## always a homeomorphism ?

Thanks.
 
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Sorry, I got it, the answer is yes. And the title is for another question I wanted to make but never did. I was trying to ask initially (when I wrote the title) under what condition claases in Thurston-Nielsen were preserved: if we have h with ## h^n \simeq Id ## and g is isotopic with h, does it follow that ## g^n \simeq Id ## (meaning g^n is isotopic to the identity )
 
As shown by this animation, the fibers of the Hopf fibration of the 3-sphere are circles (click on a point on the sphere to visualize the associated fiber). As far as I understand, they never intersect and their union is the 3-sphere itself. I'd be sure whether the circles in the animation are given by stereographic projection of the 3-sphere from a point, say the "equivalent" of the ##S^2## north-pole. Assuming the viewpoint of 3-sphere defined by its embedding in ##\mathbb C^2## as...

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