Rocket acceleration/time problem?

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SUMMARY

The discussion focuses on calculating the total time a 200kg weather rocket, loaded with 100kg of fuel, remains airborne after being fired straight up with an acceleration of 34 m/s² for 32 seconds. The rocket accelerates for the initial phase and then coasts upward after fuel depletion. Key equations utilized include d = Vi*t + 1/2*a*t² and Vf = Vi + at, which help determine the distance traveled during both the powered ascent and the subsequent free flight phase.

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Homework Statement



A 200kg weather rocket is loaded with 100kg of fuel and fired straight up. It accelerates upward at 34m/s^2 for 32s , then runs out of fuel. Ignore any air resistance effects.

how long is the rocket in the air?

Homework Equations


d=Vit +1/2at^2
Vf=Vi + at
V=d/t?
and possibly Vf^2=vi^2 +2ad


The Attempt at a Solution



Ok so i calculated the rockets average velocity which is 78km (i have to use 2 sig figs), don't know if that's revenant though.

Also is the weights even a part of the problem? or is it a trick?

I figured out that this problem has 2 parts, the part where its accelerating and the one where the fuel runs out but its still going upward.

from the question it says 32s (which is for the first part) so do i have to find the distance for the 2nd part and just add them? some help would be very welcome :)
 
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Calculate how far up it'll be once it runs out of fuel then use d=h +1/2at^2 (h being the height)
 

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