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A 500m high volcano eject rocks at a speed 30 m/s.What is max horizontal distance reached by the rock?
The maximum horizontal distance a rock can travel when ejected from a 500m high volcano at a speed of 30 m/s is calculated using projectile motion equations. The relevant equations include the range formula, range = [(V initial)^2 x (sin 2A)]/[g], and the vertical motion formula, y = yo + v*t - 0.5*g*t^2. The angle of projection should be 45 degrees for optimal range, and the gravitational acceleration is 9.8 m/s². The initial calculations must account for the height of the volcano to determine the correct horizontal distance.
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