- #1

David89

- 19

- 4

## Homework Statement

On my physics 200 final from Athabasca

A volcano shoots off a rock at a 39 degree angle, at an elevation of 1200m, and the rock has a horizontal range of 5500m.

X = 5500m

Y0 = 1200m

Vx = Unknown

Vy = Unknown

V = Unknown

t = Unknown

a (vertical) = g = -9.8 m/s^2

## Homework Equations

Equation for horizontal motion: (Vx)(t) = X

Equation for vertical motion: Y = (Y0) + (Vy)(t) +0.5at^2

## The Attempt at a Solution

No idea, I don't think there is enough provided information to solve, and this question messed me up on my final pretty bad.

I did end up using the relation V0^2*sin(a)^2 / g, but I know this only works for projectile motion on level ground. I used it anyways cause I didn't know what else to do...