Roller Coaster Physics: Calculating Energy, Speed, and Force

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SUMMARY

This discussion focuses on the physics of roller coasters, specifically calculating energy, speed, and force using the example of Jessie, who has a mass of 56.2 kg and is traveling at 12.8 m/s at the top of a 19.5 m high loop. The total mechanical energy at the bottom of the loop is calculated to be 1.53 x 104 J, with Jessie's speed at that point being 23.4 m/s. The force experienced by Jessie from her seat at the bottom of the loop is determined to be 3707 N, highlighting the importance of correctly identifying the radius of the loop in calculations.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Familiarity with gravitational potential energy (mgh)
  • Knowledge of kinetic energy (1/2mv2)
  • Concept of centripetal acceleration (ac=v2/r)
NEXT STEPS
  • Review the principles of conservation of mechanical energy in physics.
  • Learn how to apply centripetal force equations in circular motion scenarios.
  • Study the effects of friction and air resistance on roller coaster dynamics.
  • Explore advanced topics in roller coaster design and safety considerations.
USEFUL FOR

Physics students, engineering students, and anyone interested in understanding the mechanics of roller coasters and the forces involved in circular motion.

Schaus
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Homework Statement


Jessie (m=56.2 kg) is traveling at a speed of 12.8 m/s at the top of a 19.5-m high roller coaster loop.

a) Assuming negligible losses of energy due to friction and air resistance, determine Jessie's total mechanical energy at the bottom of the loop (h=0 m). (ans: 1.53 x 104 J)
b) Determine Jessie's speed at the bottom of the loop. (ans: 23.4 m/s)
c)What force does Jessie feel from her seat at the bottom of the loop? (ans: 3707N)

Homework Equations


F=ma
ac=v2/r
mgh
1/2mv2

The Attempt at a Solution


I figured out a) with mgh+1/2mv2=Efinal.
I figured out b) with using energy from a) 1.53 x 104= 1/2mv2
But I can't figure out c).
I tried using ac=23.42/19.5m to find my acceleration then multiply the mass but the number isn't close to the weight I need.
 
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It looks like you used the diameter, as opposed to the radius.
 
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2nd law: Fnet = ma. Note the "net" here.
 
Think again about what the radius of the loop is.
 
Thanks! I totally missed that one and now my answer works!
 
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