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Rolling a pair of dice 20 times

  1. Mar 31, 2013 #1
    1. The problem statement, all variables and given/known data

    I have math experiment where I roll a pair of honest dice 20 times.

    The results are:

    2,3,4,4,5,5,6,6,6,7,7,7,7,7,9,9,9,10,10,11

    write a frequency table of the outcome of the dice roll with respect to size:

    2,3,4,5,6,7,8,9,10,11,12

    Firstly there must 36 possible outcomes since there two dice with 6 sides.

    This gives me a frequency table which looks as follows:

    x P(x)

    2 1/36

    3 1/36

    4 2/36

    5 2/36

    6 3/36

    7 5/36

    8 0

    9 3/36

    10 2/36

    11 1/36

    12 0

    Is this correct? By why doesn't the frequencies add up to 100%?? Is it because I only role the dice 20 times?
     
  2. jcsd
  3. Mar 31, 2013 #2

    Ray Vickson

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    Dividing by 36 would be correct if you rolled the dice 36 times---but you didn't.
     
  4. Mar 31, 2013 #3
    So I just exchange 36 with 20?
     
  5. Mar 31, 2013 #4

    Ray Vickson

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    What do YOU think?
     
  6. Mar 31, 2013 #5
    yes because I roll the dice 20 times and not 36.
     
  7. Mar 31, 2013 #6

    Ray Vickson

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    Right!
     
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