"Inverted siphons were used by the Romans to cross some valleys. If the height difference between the top of the valley and the bottom is 10 meters, the pressure in the pipe at the bottom of the valley will be ____.
P1+(pv^2)/2 + pgh1 = constant
A1V1 = A2V2
The Attempt at a Solution
I know that the density of water is 1000 kg/m3, g = 9.81 m/s2, and the height is 10 meters. I substituted these numbers into the Bernoulli's equation. However, based on the continuity equation, I cancelled the velocity in the Bernoulli's equation. The pressure on top should be 1 atmospheres due to air pressure.
(1)+(1000)/2+(1000)(9.81)(10) = P2+(1000)/2+(1000)(9.81)(10)
501 + 98100 = P2 + 98100
P2 = 501
At this point, it is obvious that is not the answer. The answer was 2 atmospheres.
Thanks for reading!