1. The problem statement, all variables and given/known data "Inverted siphons were used by the Romans to cross some valleys. If the height difference between the top of the valley and the bottom is 10 meters, the pressure in the pipe at the bottom of the valley will be ____. 2. Relevant equations Bernoulli's Equation P1+(pv^2)/2 + pgh1 = constant Continuity Equation A1V1 = A2V2 3. The attempt at a solution I know that the density of water is 1000 kg/m3, g = 9.81 m/s2, and the height is 10 meters. I substituted these numbers into the Bernoulli's equation. However, based on the continuity equation, I cancelled the velocity in the Bernoulli's equation. The pressure on top should be 1 atmospheres due to air pressure. (1)+(1000)/2+(1000)(9.81)(10) = P2+(1000)/2+(1000)(9.81)(10) 501 + 98100 = P2 + 98100 P2 = 501 At this point, it is obvious that is not the answer. The answer was 2 atmospheres. Thanks for reading!