High School Roots of Polynomials: Understanding Mathematical Methods

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The discussion revolves around the representation of polynomial functions and their roots. It clarifies that while the polynomial can be expressed as F(x) = A(x - α1)(x - α2) · · · (x - αr), it can also be represented with multiplicities as F(x) = A(x - α1)^m1(x - α2)^m2 · · · (x - αr)^mr. The key point is that both forms have the same roots, meaning they yield the same zeros, despite the differences in their structure. Raising factors to powers does not change the location of the roots; it only indicates the multiplicity of those roots. Understanding this distinction is crucial for grasping polynomial behavior in mathematical methods.
Rishabh Narula
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I was reading this book - " mathematical methods for physics and engineering"
in it in chapter 1 its says
"F(x) = A(x - α1)(x - α2) · · · (x - αr),"
this makes sense to me but then it also said

We next note that the condition f(αk) = 0 for k = 1, 2, . . . , r, could also be met
if (1.8) were replaced by
F(x) = A(x - α1)^m1(x - α2)^m2 · · · (x - αr)^mr

this confused me...how can you can you just raise each factor to powers m1,m2,...mr etc.How does the function still remain same?
 
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The function doesn't "remain the same" and this doesn't say it does. It just says that the two functions have the same zeros. Both (x- a_r) and (x- a_r)^n are 0 if and only if x= a_r.
 
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