1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rotating Square Loop in Constant B-field

  1. Apr 21, 2012 #1
    [SOLVED] Rotating Square Loop in Constant B-field

    1. The problem statement, all variables and given/known data
    2. Relevant equations

    [itex]\epsilon[/itex] = - [itex]\frac{d\Phi}{dt}[/itex]

    [itex]\Phi[/itex] = BAcos([itex]\theta[/itex]) = BAcos([itex]\omega[/itex]t)

    [itex]d\Phi[/itex] = -BA[itex]\omega[/itex]sin([itex]\omega[/itex]t)

    3. The attempt at a solution

    I'm trying to study for an exam and I've got this practice question that I can answer but my answer never matches. I keep getting b as an answer and I'm not sure if it's right.

    [itex]\epsilon[/itex] = BAcos([itex]\omega[/itex]t) = (2T)(0.2m)2(10)sin(10t)

    I use t = 2s since it asks for [itex]\theta[/itex] = 20° and I get

    [itex]\epsilon[/itex] = (2T)(0.2m)2(10)sin(20) ≈ 0.27 V

    Am I making a mistake or a wrong assumption anywhere or could it be the answer is incorrectly marked?

    Thanks!
     
    Last edited: Apr 21, 2012
  2. jcsd
  3. Apr 21, 2012 #2
    Using "10" might be fine inside the argument of the sine function, but if you're taking it outside when you take the derivative, you need to convert it to rad/s.
     
  4. Apr 21, 2012 #3
    Thanks, didn't think of that.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook