A cylinder of mass m2 and radius r rolls without slipping over a cylindrical surface. It is driven (like an inverted pendulum) by a uniform rod of mass m1 and length L. Its instantaneous position as a function of time is determined by the angular displacement
Produce the expression for the kinetic energy of the system as a function of time.[/B]
K.E(tot) = 1/2 m*v^2 + 1/2 I*omega^2
where I(cylinder 2D) = (m*r^2)/2
I(rod about fixed end)=(1/2)*m*L^2
The Attempt at a Solution
I found the velocity using the derivative of the position vector of the end of the rod which is attached to the centre of the cylinder. Now what...is this velocity considered the translational velocity of the cylinder. how do i find omega? I don't know what to do next?