Rotational Dynamics and string Tension

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The discussion revolves around a physics problem involving a light string, a solid cylinder, and a hanging mass. The mass falls 54 cm in 3 seconds, prompting calculations for the tension in the string and the mass of the cylinder. The tension was calculated to be approximately 2.979 N, but the user expressed confusion about the approach for determining the cylinder's mass. Clarifications were provided regarding the moment of inertia for a solid cylinder and the importance of drawing free body diagrams to better understand the forces involved. The user confirmed that the cylinder is freely rotating, indicating progress in their understanding of the problem.
Juniper7
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Homework Statement



A light string is wrapped around a solid cylinder and a 300g mass hangs from the free end of the string. when released, the mass falls a distance of 54cm in 3.0s.
a) Calculate the tension in the string.
b) Calculate the mass of the cylinder.

Homework Equations



y=y0 + v0t + 1/2at^2
I=mr^2
α=a/r
T-mg=ma
F=ma
τ=Iα
τ=rF

The Attempt at a Solution



a) y=y0 + v0t + 1/2at^2
0.54m = (0.5)a(3s^2)
a=0.12m/s^2

T-mg=ma
T-(0.3kg)(9.8m/s^2) = (0.3kg)(0.12m/s^2)
T=2.979N

b) τ=Iα
τ=mr^2α
Fr=mr^2α
F=mrα

I'm not sure if that's right for a), I feel like I'm missing something... :frown:
I'm very confused for b). I have been playing around with the equations, as you can see above, but I keep going in circles and I feel like I don't have enough information. Thanks in advanced for any help!
 
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Juniper7 said:

Homework Statement



A light string is wrapped around a solid cylinder and a 300g mass hangs from the free end of the string. when released, the mass falls a distance of 54cm in 3.0s.
a) Calculate the tension in the string.
b) Calculate the mass of the cylinder.

Homework Equations



y=y0 + v0t + 1/2at^2
I=mr^2
α=a/r
T-mg=ma
F=ma
τ=Iα
τ=rF

The Attempt at a Solution



a) y=y0 + v0t + 1/2at^2
0.54m = (0.5)a(3s^2)
a=0.12m/s^2

T-mg=ma
T-(0.3kg)(9.8m/s^2) = (0.3kg)(0.12m/s^2)
T=2.979N

b) τ=Iα
τ=mr^2α
Fr=mr^2α
F=mrα

I'm not sure if that's right for a), I feel like I'm missing something... :frown:
I'm very confused for b). I have been playing around with the equations, as you can see above, but I keep going in circles and I feel like I don't have enough information. Thanks in advanced for any help!
Hello Juniper7. Welcome to PF !

First of all, there is at least one missing detail. Is the cylinder free to rotate on its axis ?

The form of the moment of inertial you have, I = mr2 is for a hollow cylinder, not a solid one.

You use both F and T, somewhat interchangeably.


Draw 2 free body diagrams; one for the hanging mass, and one for the cylinder?

Doing these things should help take the guesswork out of what equations to employ.
 
Oh, ok. I think I have it now. The cylinder is freely rotating. Thanks!
 
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