Rotational dynamics of two cars

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SUMMARY

The discussion centers on the rotational dynamics of two cars racing on a circular track, with Car A accelerating at 0.340 rad/s² and Car B at 0.270 rad/s². Car B starts first with an initial angular velocity of 1.40 rad/s. After calculating the time Car B accelerates before Car A begins to move (5.185 seconds) and the distance it travels (3.629), the user applies linear motion equations to determine that Car A catches up to Car B at approximately 47.625 seconds. However, discrepancies arise when verifying the distances traveled by both cars at these times.

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  • Understanding of angular acceleration and velocity
  • Familiarity with linear motion equations
  • Knowledge of quadratic equations and their applications
  • Basic principles of rotational dynamics
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  • Study the application of angular motion equations in racing scenarios
  • Learn about the relationship between angular acceleration and distance traveled
  • Explore the use of quadratic equations in motion problems
  • Investigate the effects of initial conditions on motion equations
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Students studying physics, particularly those focusing on rotational dynamics, as well as educators and tutors assisting with kinematics problems involving angular motion.

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Homework Statement


Two cars race around a circular track. Car A accelerates at 0.340 rad/s2 around the track, and car B at 0.270 rad/s2. They start at the same place on the track and car A let's the slower-to-accelerate car B start first. Car B starts at time t = 0. When car A starts, car B has an angular velocity of 1.40 rad/s. At what time does car A catch up to car B?


The Attempt at a Solution



So first I calculated the time that car B accelerates before car A begins to move using acceleration of car B and its final angular velocity.

My time value is 5.185

Then I calculated the distance that car B travels until it attains an angular velocity of 1.4.

My distance is 3.629.

Then I used the linear motion equations to set the final distances of cars A and B to one another, resulting in the following equation after simplified:

1/2 Alpha(car A) t^2 - 1/2 Alpha(car B) t^2 - Omega (initial car B) t - Theta (car B).

After plugging in values, I used the quadratic equation and found a time value of 42.44 seconds.

I added the time that Car B travels before it reaches car A: 5.185 + 42.44 and found an ultimate time of 47.625.

But if I plug each the smaller time into car A's linear motion equation and the larger into Car B's, the distances are unequal...

help...?

Thank you in advance.
 
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When you plug the longer time into the slower cars equation it's changed. The proper equation for that car then has no initial conditions.

X = 1/2*.27*(47.625)2 = 1/*.34*(42.44)2
 

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